<![CDATA[Ability to use jokers in File.Count(*)]]>Ability to use jokers in File.Count(*)

It would be nice to have ability to use jokers
in File.Count parameter. For instance if you have

x:\folderA\subfolder\a\file1.txt
x:\folderA\subfolder\b\file2.txt
x:\folderA\subfolder\c\file3.txt
x:\folderA\subfolder\c\file4.txt

File.Count(x:\folderA\subfolder\*\*)
or
File.Count(x:\folderA\*\*\*)

Would return: 4

Or add additional DCI: File.CountEx(*)

File.CountEx(<root_path>,<depth>)

File.CountEx(x:\folderA,2)
Would return: 4

thank you,

Ales

]]>https://forum.netxms.org/topic/310/ability-to-use-jokers-in-file.countRSS for NodeFri, 13 Nov 2026 16:29:07 GMTFri, 18 Apr 2008 11:27:45 GMT60<![CDATA[Reply to Ability to use jokers in File.Count(*) on Sun, 20 Apr 2008 18:55:58 GMT]]>Thank you 🙂

A

]]>https://forum.netxms.org/post/1515https://forum.netxms.org/post/1515Sun, 20 Apr 2008 18:55:58 GMT<![CDATA[Reply to Ability to use jokers in File.Count(*) on Sat, 19 Apr 2008 16:47:28 GMT]]>Hello!

It is possible already. File.Count has the following arguments:

File.Count(root_path, [pattern], [recursive])

You can define pattern as usual with * and ? characters, and if you wish to scan directories recursively, you should pass 1 as recursive arguments.

For your example

x:\folderA\subfolder\a\file1.txt
x:\folderA\subfolder\b\file2.txt
x:\folderA\subfolder\c\file3.txt
x:\folderA\subfolder\c\file4.txt

File.Count(x:\FolderA, *, 1) will return 4
File.Count(x:\FolderA, file2.*, 1) will return 1
File.Count(x:\FolderA, *) will return 0

Best regards,
Victor

]]>https://forum.netxms.org/post/1514https://forum.netxms.org/post/1514Sat, 19 Apr 2008 16:47:28 GMT