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  1. Home
  2. Support (Russian)
  3. Поиск интерфейса по его Description

Поиск интерфейса по его Description

Scheduled Pinned Locked Moved Support (Russian)
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  • A
    A
    Argonauts
    wrote on last edited by
    #1

    Добрый день.
    Как можно проводить поиск по конкретным значениям какого-либо параметра в нодах?
    В ветке Делимся скриптами сразу в шапке имелся скрипт поиска "в данном случае по snmp sysDescription коммутатора"

    sub GetTree (nodeID)
    {
    Tree = FindObject(nodeID);
    children = GetObjectChildren(Tree);
    
    foreach (n : children)
    {
        //println ("Name: " . n->name);
        if (n->name != null && classof(n) == "Node")
        {
            if (n->sysDescription ~= "^D-Link DES-3028" && n->comments == "")
        {
            println ("Name: " . n->name . ", sysDescription: " . n->sysDescription . ", IP: " . n->ipAddr);
        }
    }
    GetTree(n->id);
      }
    }
    
    GetTree(2);
    

    Который я попытался перенаправить на поиск нод, в которых Description на каком-то из интерфейсов имеет WAN.

    sub GetTree (nodeID)
    {
    Tree = FindObject(nodeID);
    children = GetObjectChildren(Tree);
    
    foreach (n : children)
    {
        //println ("Name: " . n->name);
        if (n->name != null && classof(n) == "Node")
        {
            if (n->interfaces.description ~= "WAN" && n->comments == "")
        {
            println ("Name: " . n->name . ", interfaces.description: " . n->interfaces.description . ", IP: " . n->ipAddr);
        }
    }
    GetTree(n->id);
      }
    }
    
    GetTree(2);
    

    Но оба скрипта падают в syntax error на линию 13. Что с того момента изменилось в синтаксе?
    =================
    Edited
    В таком виде

    sub GetTree(nodeID)
    {
        Tree = FindObject(nodeID);
        children = GetObjectChildren(Tree);
    
        foreach (n : children)
        {
            if (n->name != null && classof(n) == "Node")
            {
                ifaces = n->interfaces;
                foreach (iface : ifaces)
                {
                    if (iface->description ~= "WAN")
                    {
                        println("Name: " , n->name , ", interface: " , iface->description , ", IP: " , iface->ipAddr);
                    }
                }
    
                GetTree(n->id);
            }
        }
    }
    
    GetTree(2);
    

    выполнение его проходит, но результат никакой не получается

    *** FINISHED ***
    
    Result:
    
    1 Reply Last reply
    0
    • A
      A
      Alex Kirhenshtein
      wrote on last edited by
      #2
      function GetTree(nodeID)
      {
          obj = FindObject(nodeID);
          if (obj == null) return;
      
          children = obj.children;
      
          for (n : children)
          {
              if (classof(n) == "Node")
              {
                  ifaces = n.interfaces;
                  for (iface : ifaces)
                  {
                      if (iface.description ~= "WAN")
                      {
                          println("Node: " .. n.name .. ", Interface: " .. iface.name .. ", Description: " .. iface.description .. ", IP: " .. iface.ipAddr);
                      }
                  }
              }
              // Рекурсия ВЫНЕСЕНА за пределы условия - обходим все контейнеры
              GetTree(n.id);
          }
      }
      
      GetTree(2);
      

      Основные изменения:

      • function вместо sub — современный синтаксис
      • obj.children вместо GetObjectChildren(obj)
      • . вместо -> для доступа к свойствам
      • .. для конкатенации строк (вместо , в println)
      • Рекурсия вынесена за пределы условия classof(n) == "Node"
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      0

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