Skip to content
  • Categories
  • Recent
  • Tags
  • Popular
  • Users
  • Groups
Skins
  • Light
  • Brite
  • Cerulean
  • Cosmo
  • Flatly
  • Journal
  • Litera
  • Lumen
  • Lux
  • Materia
  • Minty
  • Morph
  • Pulse
  • Sandstone
  • Simplex
  • Sketchy
  • Spacelab
  • United
  • Yeti
  • Zephyr
  • Dark
  • Cyborg
  • Darkly
  • Quartz
  • Slate
  • Solar
  • Superhero
  • Vapor

  • Default (Flatly)
  • No Skin
Collapse
Brand Logo

NetXMS Forum

  1. Home
  2. Feature Requests
  3. Ability to use jokers in File.Count(*)

Ability to use jokers in File.Count(*)

Scheduled Pinned Locked Moved Feature Requests
3 Posts 2 Posters 20.5k Views
  • Oldest to Newest
  • Newest to Oldest
  • Most Votes
Reply
  • Reply as topic
Log in to reply
This topic has been deleted. Only users with topic management privileges can see it.
  • S
    S
    sodalist
    wrote on last edited by
    #1

    Ability to use jokers in File.Count(*)

    It would be nice to have ability to use jokers
    in File.Count parameter. For instance if you have

    x:\folderA\subfolder\a\file1.txt
    x:\folderA\subfolder\b\file2.txt
    x:\folderA\subfolder\c\file3.txt
    x:\folderA\subfolder\c\file4.txt

    File.Count(x:\folderA\subfolder\*\*)
    or
    File.Count(x:\folderA\*\*\*)

    Would return: 4

    Or add additional DCI: File.CountEx(*)

    File.CountEx(<root_path>,<depth>)

    File.CountEx(x:\folderA,2)
    Would return: 4

    thank you,

    Ales

    1 Reply Last reply
    0
    • V
      V
      Victor Kirhenshtein
      wrote on last edited by
      #2

      Hello!

      It is possible already. File.Count has the following arguments:

      File.Count(root_path, [pattern], [recursive])

      You can define pattern as usual with * and ? characters, and if you wish to scan directories recursively, you should pass 1 as recursive arguments.

      For your example

      x:\folderA\subfolder\a\file1.txt
      x:\folderA\subfolder\b\file2.txt
      x:\folderA\subfolder\c\file3.txt
      x:\folderA\subfolder\c\file4.txt

      File.Count(x:\FolderA, *, 1) will return 4
      File.Count(x:\FolderA, file2.*, 1) will return 1
      File.Count(x:\FolderA, *) will return 0

      Best regards,
      Victor

      1 Reply Last reply
      0
      • S
        S
        sodalist
        wrote on last edited by
        #3

        Thank you πŸ™‚

        A

        1 Reply Last reply
        0

        Hello! It looks like you're interested in this conversation, but you don't have an account yet.

        Getting fed up of having to scroll through the same posts each visit? When you register for an account, you'll always come back to exactly where you were before, and choose to be notified of new replies (either via email, or push notification). You'll also be able to save bookmarks and upvote posts to show your appreciation to other community members.

        With your input, this post could be even better πŸ’—

        Register Login
        Reply
        • Reply as topic
        Log in to reply
        • Oldest to Newest
        • Newest to Oldest
        • Most Votes


        • Login

        • Don't have an account? Register

        • Login or register to search.
        Powered by NodeBB Contributors
        • First post
          Last post
        0
        • Categories
        • Recent
        • Tags
        • Popular
        • Users
        • Groups